Principles of Inheritance and Variation

Covers NCERT Class 12 Biology, Chapter "Principles of Inheritance and Variation" — Mendelian genetics, chromosomal theory, sex determination, mutation and human genetic disorders. One of the most reliably tested chapters across recent NEET papers.

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⭐ NTA-favourite subtopics in this chapter

Monohybrid & dihybrid cross ratios and test-cross applications, incomplete dominance vs co-dominance (flower colour, ABO blood group), multiple alleles and pleiotropy, chromosomal theory of inheritance and linkage, sex-determination mechanisms (XX-XY, XO, ZW), pedigree symbols and pattern recognition, and human genetic disorders — both Mendelian (haemophilia, colour blindness, sickle-cell anaemia, thalassemia, PKU) and chromosomal (Down, Klinefelter, Turner syndrome).

Exam-oriented notes

NCERT-tagged theory, simplified

NCERT §5.1

Mendel's Law of Dominance: in a heterozygote, one allele (dominant) expresses over the other (recessive). Law of Segregation: the two alleles of a gene separate during gamete formation, each gamete getting only one. Law of Independent Assortment: alleles of different genes (on different chromosome pairs) segregate independently of each other.

NCERT §5.2

A test cross (heterozygote × homozygous recessive) is used to determine an organism's actual genotype when the phenotype alone can't distinguish homozygous dominant from heterozygous. Monohybrid test cross gives a 1:1 ratio.

NCERT §5.2

Incomplete dominance (e.g. Mirabilis jalapa flower colour) gives an intermediate F1 phenotype and a 1:2:1 phenotypic ratio in F2 — genotypic and phenotypic ratios become identical, unlike simple Mendelian dominance.

NCERT §5.2

Co-dominance: both alleles express fully and simultaneously — classic example is the AB blood group, where both I^A and I^B alleles are expressed together on the same red blood cells.

NCERT §5.2

ABO blood group is controlled by multiple alleles (I^A, I^B, i) at a single locus, with I^A and I^B co-dominant over i, and both dominant to i.

NCERT §5.3

Independent dihybrid cross gives a classic 9:3:3:1 F2 phenotypic ratio; linked genes (located close together on the same chromosome) deviate from this ratio because they don't assort independently — Morgan's Drosophila work established this.

NCERT §5.4

Sex determination: humans and most mammals use the XX (female)–XY (male) system; grasshoppers use XX–XO; birds/some reptiles use ZW–ZZ (female is the heterogametic sex, opposite to mammals); honeybees use haplodiploidy (no sex chromosomes at all).

NCERT §5.5

Mutation is any sudden, heritable change in DNA sequence — point mutations (single base change, e.g. sickle-cell anaemia) versus chromosomal aberrations (changes in chromosome number/structure, e.g. Down syndrome's trisomy 21).

NCERT §5.6

Pedigree analysis uses standard symbols (square = male, circle = female, filled = affected, horizontal line = mating, vertical line = offspring) to trace inheritance patterns across generations in humans, where controlled crosses aren't possible.

Printable

Ratio & disorder data sheet

Genetics — key ratios & numbers

Monohybrid F2 phenotypic ratio
3 : 1
Monohybrid F2 genotypic ratio
1 : 2 : 1
Dihybrid F2 phenotypic ratio
9 : 3 : 3 : 1
Monohybrid test cross ratio
1 : 1
Dihybrid test cross ratio
1 : 1 : 1 : 1
Down syndrome
Trisomy 21 (47 chromosomes)
Klinefelter syndrome
47, XXY
Turner syndrome
45, X (XO)
Colour blindness / haemophilia
X-linked recessive
Sickle-cell anaemia
Autosomal recessive, point mutation (Glu→Val)
PYQ-style practice

Practice set, NEET pattern

Original questions modelled on recurring NEET question types — not verbatim reproductions of any official paper.

Q1. A cross between a red-flowered (RR) and white-flowered (rr) Mirabilis jalapa plant produces pink F1. This is an example of:
  • Co-dominance
  • Incomplete dominance
  • Multiple allelism
  • Pleiotropy
Show solution
Neither allele fully dominates; the heterozygote shows a blended, intermediate phenotype — incomplete dominance. Answer: B
Q2. A man with blood group AB marries a woman with blood group O. Their children can have blood group:
  • Only AB
  • Only O
  • A or B only
  • AB or O
Show solution
Father is I^AI^B, mother is ii. Offspring genotypes: I^Ai (blood group A) or I^Bi (blood group B) — never AB or O from this cross. Answer: C
Q3. Down syndrome results from:
  • Deletion of a part of chromosome 21
  • An extra copy of chromosome 21 (trisomy)
  • Loss of one X chromosome
  • An extra X chromosome in a male
Show solution
Down syndrome is trisomy 21 — an individual has three copies of chromosome 21 instead of two, total 47 chromosomes. Answer: B
Q4. A colour-blind man marries a woman who is homozygous normal. What fraction of their sons will be colour-blind?
  • 0%
  • 25%
  • 50%
  • 100%
Show solution
Sons get their X chromosome only from the mother (who is X^N X^N); the father's X^c X chromosome goes only to daughters. All sons will be normal. Answer: A
Q5. In a dihybrid test cross (AaBb × aabb), the expected phenotypic ratio in offspring, assuming independent assortment, is:
  • 9:3:3:1
  • 1:1
  • 3:1
  • 1:1:1:1
Show solution
Crossing a dihybrid with a fully recessive homozygote directly reveals the gamete ratio of the heterozygote — 1:1:1:1. Answer: D
Q6. Which sex-determination system is found in birds?
  • XX–XY, male heterogametic
  • XX–XO
  • ZW–ZZ, female heterogametic
  • Haplodiploidy
Show solution
In birds, the female is ZW (heterogametic) and the male is ZZ (homogametic) — the reverse of the mammalian pattern. Answer: C
Daily Practice Problems

DPP — Principles of Inheritance and Variation (15 questions)

Scaled from direct NCERT recall (Q1–Q6) to mixed NEET-level difficulty (Q7–Q15).

1.State Mendel's Law of Segregation.
2.Define test cross and state its purpose.
3.Give the genotype and phenotype possibilities for the ABO blood group system.
4.Name the chromosomal disorder caused by 47, XXY and state whether it affects males or females.
5.What is the chromosomal basis of Turner syndrome?
6.List two X-linked recessive disorders in humans.
7.A tall pea plant (Tt) is crossed with another tall pea plant (Tt). Find the phenotypic ratio in the offspring.
8.Explain why linked genes do not show the expected 9:3:3:1 dihybrid ratio.
9.A haemophilic man (X^h Y) marries a carrier woman (X^H X^h). Find the probability their daughter is haemophilic.
10.Differentiate between point mutation and chromosomal aberration, with one example each.
11.In sickle-cell anaemia, identify the amino acid substitution and the chromosome involved.
12.Draw (describe in words) the standard pedigree symbol for an affected female and an unaffected male.
13.Explain pleiotropy with a suitable example.
14.A dihybrid cross AaBb × AaBb produces 16 possible combinations. How many of these are homozygous for both traits?
15.Assertion: All Down syndrome cases arise from non-disjunction during meiosis in a parent. Reason: Non-disjunction leads to gametes with an abnormal chromosome number. Judge the pair.
Show answer key
1. The two alleles of a gene separate during gamete formation, each gamete receiving only one  |  2. Cross with homozygous recessive, to reveal unknown genotype from offspring ratio  |  3. I^AI^A/I^Ai → A; I^BI^B/I^Bi → B; I^AI^B → AB; ii → O  |  4. Klinefelter syndrome, affects males  |  5. Only one X chromosome (45, X / XO)  |  6. Colour blindness, haemophilia  |  7. 3 tall : 1 dwarf  |  8. They are physically close on the same chromosome and tend to be inherited together rather than assorting independently  |  9. 50% (daughters get X^h from father always; mother contributes X^H or X^h with equal chance, giving carrier or affected daughters in a 1:1 ratio)  |  10. Point mutation = single base change (sickle-cell anaemia); chromosomal aberration = change in chromosome number/structure (Down syndrome)  |  11. Glutamic acid → Valine at position 6 of the beta-globin chain, chromosome 11  |  12. Filled circle = affected female; open/unfilled square = unaffected male  |  13. One gene affecting multiple, seemingly unrelated phenotypic traits, e.g. phenylketonuria affecting both mental and pigmentation traits  |  14. 4 of 16 (AABB, AAbb, aaBB, aabb)  |  15. Both true, reason correctly explains assertion — though note most (not literally "all" in the strictest technical sense across rare mosaic cases) arise this way, which is the usual intended reading at this level
Story mode

A memory-only mythology narrative for inheritance

Purely a recall device — not a reinterpretation of the source stories.

📖 The twin heirs — dominant and recessive alleles

Think of a family with two possible heirs to a throne, one loud and visible in every portrait (the dominant allele), one quiet and unseen unless both parents happen to carry only that quiet line (the recessive allele, expressed only when homozygous). In each generation, only one heir's trait is painted into the portrait — but the quiet heir's blood never disappears, just waits, exactly as Mendel's Law of Segregation describes: both alleles are passed on and separate cleanly into gametes, even when only one is seen.

📖 Kubera's ledger — multiple alleles of the ABO system

Picture a treasurer's ledger with three possible entries at one single account line — I^A, I^B, and i — but every person only carries two of the three at once. I^A and I^B are both "loud" entries that show up equally when they appear together (co-dominance, giving blood group AB); i is the "silent" entry, visible only when no loud entry is present at all (giving blood group O). One locus, three possible entries, but always exactly two per ledger — the essence of multiple allelism.

🧠 Ratio recall, one line

"3-1 alone, 9-3-3-1 together, 1-1 when tested" — monohybrid F2 is 3:1, dihybrid F2 is 9:3:3:1, and any test cross collapses back to equal ratios (1:1 or 1:1:1:1) because the recessive parent contributes nothing but a "blank" gamete.